Quadratic Formula Calculator
Solve quadratic equations of the form ax² + bx + c = 0 using the quadratic formula. Find roots, vertex, discriminant, and graph properties with step-by-step solutions.
Quadratic Equation: ax² + bx + c = 0
Your Equation:
Quick Examples
Discriminant Analysis
Formula: Δ = b² - 4ac
- Δ > 0: Two distinct real roots
- Δ = 0: One repeated real root
- Δ < 0: Two complex conjugate roots
Solutions
Parabola Properties
Step-by-Step Solution
How to Use This Calculator
This quadratic formula calculator solves equations of the form ax² + bx + c = 0 and provides comprehensive analysis.
- Enter the coefficients a, b, and c for your quadratic equation
- The calculator will automatically compute the discriminant and determine the nature of roots
- View the solutions, vertex, axis of symmetry, and other parabola properties
- Follow the step-by-step solution to understand the calculation process
- Use quick examples to see how different types of quadratic equations are solved
Understanding the Quadratic Formula
The Formula
The quadratic formula is: x = (-b ± √(b² - 4ac)) / (2a)
Key Components
- Discriminant (Δ): b² - 4ac determines the nature of roots
- Vertex: The turning point of the parabola at (-b/2a, f(-b/2a))
- Axis of Symmetry: The vertical line x = -b/2a
- Roots: The x-intercepts where the parabola crosses the x-axis
Types of Solutions
- Two Real Roots: When Δ > 0, the parabola crosses the x-axis twice
- One Real Root: When Δ = 0, the parabola touches the x-axis once (vertex on x-axis)
- Complex Roots: When Δ < 0, the parabola doesn't cross the x-axis
Vieta's Formulas
- Sum of roots: x₁ + x₂ = -b/a
- Product of roots: x₁ × x₂ = c/a
Example Calculations
Example 1: Two Real Roots
Solve: x² - 5x + 6 = 0
Solution: a = 1, b = -5, c = 6
Δ = (-5)² - 4(1)(6) = 25 - 24 = 1
x = (5 ± √1) / 2 = (5 ± 1) / 2
x₁ = 3, x₂ = 2
Example 2: One Repeated Root
Solve: x² - 4x + 4 = 0
Solution: a = 1, b = -4, c = 4
Δ = (-4)² - 4(1)(4) = 16 - 16 = 0
x = 4 / 2 = 2 (repeated root)
Example 3: Complex Roots
Solve: x² + x + 1 = 0
Solution: a = 1, b = 1, c = 1
Δ = 1² - 4(1)(1) = 1 - 4 = -3
x = (-1 ± √(-3)) / 2 = (-1 ± i√3) / 2
Frequently Asked Questions
What if the coefficient 'a' is zero?
If a = 0, the equation becomes linear (bx + c = 0) rather than quadratic. The quadratic formula doesn't apply, and the solution is simply x = -c/b (provided b ≠ 0).
How do I interpret complex roots?
Complex roots occur when the discriminant is negative. They come in conjugate pairs (a + bi and a - bi) and indicate that the parabola doesn't intersect the x-axis. These roots are still mathematically valid solutions.
Can I use this for incomplete quadratic equations?
Yes! If b = 0 or c = 0, simply enter 0 for that coefficient. For example, x² - 4 = 0 would have a = 1, b = 0, c = -4.
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